unable to use method type for popup input dialog

[ann LeParticipant]

Need help, I am unable to use method type for popup dialog input required
Thanks,
Ann

[Sergey ZAPKeymaster]

Hello akiwa_98,

Please try the following steps:

1. Scan your popup dialog using different Application object.

2. (if Step 1 does not help) In the Application object set property Activate Window=False.

[ann LeParticipant]

another dial bubble / dialog report failure even though the cell click is correct but the respond is not and it is hard to debug. I want to type “4289#”
*code*
‘Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell 2,1
‘Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell 1,2
‘Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell 3,3
‘Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell 3,2
‘Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell 4,3
Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell “4”
Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell “2”
Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell “9”
Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell “8”
Application(“winConXapp”).View(“incorrectPIN”).Object(“iKeyPad”).Table(“KeyPad_table”).ClickCell “#”

Attachments:

• Results-ConXApp-07-31-1910-44-38-17287f1992fdbe83c5cae029bb83380a.pdf

[Sergey ZAPKeymaster]

Please explain what your issue is.
Does it click the keys 4289# correctly? Does it loose focus of the dialog after that? What do you do in steps 361, 362?

[ann LeParticipant]

Yes, visually look correct but the result show difference and the response of my application is also incorrect. step361 and 362 is after the key 4298# was clicked the keypad should also disappeared check condition.

[Sergey ZAPKeymaster]

You said that response of your application is incorrect. Does it mean the keys clicked are incorrect? If so, please consider clicking on table cells using row and column instead of cell text (ie. ‘ClickCell 2,1’ instead of ‘ClickCell “4”‘).
To verify that the Dial dialog disappears you can use NotExist method (applied to any object inside the dialog).

[ann LeParticipant]

I did also try the ClickCell 2,1 but got the same result as ClickCell “4” don’t know why but when I look at the execution the steps and mouse click are all correct

Thank you for the NotExist Method — I will try. Thanks again,

[ann LeParticipant]

Can you give me the example of NotExist method — I did not see this method is available in the document. Thanks

[Sergey ZAPKeymaster]

Also this can be timing issue – ZAPTEST may click keys to fast. Try to add 1 second WAIT step between clicks (wait 1).

NotExist method:
Application(“Application”).View(“View”).Object(“Test1”).NotExist – this will wait/check that the object is not visible on AUT. The step fails if the object is still visible after timeout.

[ann LeParticipant]

Work for popup dialog (after ((if Step 1 does not help) In the Application object set property Activate Window=False.) but having other issue that the active windows now can not make it active after other windows display on top. Please help! Thanks

[Sergey ZAPKeymaster]

You should use “Activate Window=False” only for the pop-up dialog. The main window application object should have this property equal “true”.

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